C Program to do Arithmetic Operation Using Switch Case

   A control statement which allows us to make decision from member of choice is called switch-case-default.these three keywords go together and make a control statement. Switch statement has more than two options,these options are called cases.


Program:

//C Program to Perform Arithmetic Operation Using Switch  Case by Slashmycode.com
#include<stdio.h>
#include<conio.h>
void main()
{
int num1,num2,choice;

printf("\n 1.Addition \n 2.Subtraction \n 3.Multiplication \n 4.Division");
printf("\nEnter the choice\t");
scanf("%d",&choice);
printf("Enter the first number");
scanf("%d",&num1);
printf("Enter the second number");
scanf("%d",&num2);
switch(choice)
          {
          case 1:
          printf("The addition of %d + %d = %d",num1,num2,num1+num2);
          break;
          case 2:
          printf("The subtraction of %d - %d = %d",num1,num2,num1-num2);
          break;
          case 3:
          printf("The multiplication of %d * %d = %d",num1,num2,num1*num2);
          break;
          case 4:
          printf("The division of %d / %d = %d",num1,num2,num1/num2);
          break;
          default:
          printf("The choice is invalid");
          }
//C Program to Perform Arithmetic Operation Using Switch  Case by Slashmycode.com
getch();
}

Output:

Algorithm:

  1.  Start 
  2.  Define a,b,c,d
  3.  Give choices Addition,Subtraction,Multiplication,Division
  4.  Enter choice
  5.  Enter Two Numbers
  6.  Check for choice
  7.  If choice==1
          printf num1+num2
          step 12
        else step 8
  8. If choice==2
          printf num1-num2
          step 12
        else step 9
  9. If choice ==3
         printf num1*num2
         step 12
        else step 10
10. If choice==4
         printf num1/num2
         step 12 
       else step 11
11. Choice is invalid

12. Stop